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Gabialvescamelo
@Gabialvescamelo
April 2020
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Por favor,me ajudem com essa questão Se 2senX + cosX = Raíz de 3 o valor de tg²X+4tgX=???
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mozarthrocha
Sen x = a
cos x = b
tg²x = (a²/b²)
4tgx = 4(a/b)
tg²x + 4tgx = (a²/b²) / 4(a/b) = a²/b² . 4b/4a = 4a²b/4ab² = a/b = senx/cosx
senx/cosx = \/3
tg x = \/3
tg²x = (\/3)² =3
4tgx = 4\/3
= 3+4\/3
1 votes
Thanks 1
Gabialvescamelo
Obrigada. :)
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Lista de comentários
cos x = b
tg²x = (a²/b²)
4tgx = 4(a/b)
tg²x + 4tgx = (a²/b²) / 4(a/b) = a²/b² . 4b/4a = 4a²b/4ab² = a/b = senx/cosx
senx/cosx = \/3
tg x = \/3
tg²x = (\/3)² =3
4tgx = 4\/3
= 3+4\/3