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SrVictor2003
@SrVictor2003
November 2019
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Qual a coordenada y do vértice da função y = -x ao quad - 4x +5
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FroyRaeken
-x²-4x+5=0
∆ = b²-4ac
∆ = (-4)²-4.(-1).5
∆ = 16+20 = 36
Yv = -∆/4a
Yv = -36/4(-1) = -36/-4
Yv = 9
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∆ = b²-4ac
∆ = (-4)²-4.(-1).5
∆ = 16+20 = 36
Yv = -∆/4a
Yv = -36/4(-1) = -36/-4
Yv = 9