Articles
Register
Sign In
Search
Punkcarloshc
@Punkcarloshc
January 2020
1
24
Report
Qual a equação geral da reta que passa pelos pontos (5,2) e (7,5)?
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms and service
You must agree before submitting.
Send
Lista de comentários
Rodrigo3200
Usando a regra de Sarrus
I x y 1 I x y
I 5 2 1 I 5 2 = 0 2x + 7y + 25 - 14 - 5x - 5y = 0
I 7 5 1 I 7 5
-3x + 2y + 11 = 0 x(-1)
3x - 2y - 11 = 0
Outra maneira:
y = y1 - y2 5 - 2 3
---------- = ------- = --
x1 - x2 7 - 5 2
y - yo = m(x - xo)
y - 2 = 3/2(x - 5) x2
2y - 4 = 3(x - 5)
2y - 4 = 3x - 15
3x - 2y - 15 + 4 = 0
3x - 2y - 11 = 0
0 votes
Thanks 1
More Questions From This User
See All
punkcarloshc
March 2022 | 0 Respostas
Responda
Punkcarloshc
January 2020 | 0 Respostas
Responda
Punkcarloshc
January 2020 | 0 Respostas
Responda
Punkcarloshc
January 2020 | 0 Respostas
Responda
Punkcarloshc
January 2020 | 0 Respostas
Responda
Punkcarloshc
January 2020 | 0 Respostas
Responda
Punkcarloshc
January 2020 | 0 Respostas
Responda
Recomendar perguntas
Deividyfreitas
May 2020 | 0 Respostas
BlackShot
May 2020 | 0 Respostas
Vanessakellen
May 2020 | 0 Respostas
Guiduarter
May 2020 | 0 Respostas
Mrzaine
May 2020 | 0 Respostas
O QUE SERIA AUTONOMIA?
Grazifer
May 2020 | 0 Respostas
Joazinho
May 2020 | 0 Respostas
a palavra rapidez formou se de qual derivacao
Celiana
May 2020 | 0 Respostas
Joazinho
May 2020 | 0 Respostas
Anatercia
May 2020 | 0 Respostas
×
Report "Qual a equação geral da reta que passa pelos pontos (5,2) e (7,5)?.... Pergunta de ideia de Punkcarloshc"
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
Sobre nós
Política de Privacidade
Termos e Condições
direito autoral
Contate-Nos
Helpful Social
Get monthly updates
Submit
Copyright © 2024 ELIBRARY.TIPS - All rights reserved.
Lista de comentários
I x y 1 I x y
I 5 2 1 I 5 2 = 0 2x + 7y + 25 - 14 - 5x - 5y = 0
I 7 5 1 I 7 5
-3x + 2y + 11 = 0 x(-1)
3x - 2y - 11 = 0
Outra maneira:
y = y1 - y2 5 - 2 3
---------- = ------- = --
x1 - x2 7 - 5 2
y - yo = m(x - xo)
y - 2 = 3/2(x - 5) x2
2y - 4 = 3(x - 5)
2y - 4 = 3x - 15
3x - 2y - 15 + 4 = 0
3x - 2y - 11 = 0