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Punkcarloshc
@Punkcarloshc
January 2020
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Qual a equação geral da reta que passa pelos pontos (5,2) e (7,5)?
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Rodrigo3200
Usando a regra de Sarrus
I x y 1 I x y
I 5 2 1 I 5 2 = 0 2x + 7y + 25 - 14 - 5x - 5y = 0
I 7 5 1 I 7 5
-3x + 2y + 11 = 0 x(-1)
3x - 2y - 11 = 0
Outra maneira:
y = y1 - y2 5 - 2 3
---------- = ------- = --
x1 - x2 7 - 5 2
y - yo = m(x - xo)
y - 2 = 3/2(x - 5) x2
2y - 4 = 3(x - 5)
2y - 4 = 3x - 15
3x - 2y - 15 + 4 = 0
3x - 2y - 11 = 0
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I x y 1 I x y
I 5 2 1 I 5 2 = 0 2x + 7y + 25 - 14 - 5x - 5y = 0
I 7 5 1 I 7 5
-3x + 2y + 11 = 0 x(-1)
3x - 2y - 11 = 0
Outra maneira:
y = y1 - y2 5 - 2 3
---------- = ------- = --
x1 - x2 7 - 5 2
y - yo = m(x - xo)
y - 2 = 3/2(x - 5) x2
2y - 4 = 3(x - 5)
2y - 4 = 3x - 15
3x - 2y - 15 + 4 = 0
3x - 2y - 11 = 0