Articles
Register
Sign In
Search
Faelopanda
@Faelopanda
December 2019
1
115
Report
Qual a função f (x) = a x b , cujo gráfico passa pelos pontos ( -1, 0) e (0,5)?
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms and service
You must agree before submitting.
Send
Lista de comentários
Left123
Seja a lei de formação:
f (x) = ax + b
Temos:
0 = a (-1) + b (I)
5 = a (0) + b (II)
De (II)
5 = 0 + b => b = 5
levando para (I)
0 = -a + b
0 = -a + 5
-5 = -a => a = 5
Então:
f (x) = 5x + 5
0 votes
Thanks 1
More Questions From This User
See All
Faelopanda
December 2019 | 0 Respostas
Responda
Faelopanda
December 2019 | 0 Respostas
Preciso de um resumo de cloroplastos por favor ;-;
Responda
Faelopanda
December 2019 | 0 Respostas
Responda
Faelopanda
December 2019 | 0 Respostas
Responda
Faelopanda
December 2019 | 0 Respostas
Responda
Faelopanda
December 2019 | 0 Respostas
Responda
Faelopanda
December 2019 | 0 Respostas
Responda
Faelopanda
December 2019 | 0 Respostas
Responda
Faelopanda
December 2019 | 0 Respostas
Responda
Faelopanda
December 2019 | 0 Respostas
Responda
Recomendar perguntas
Deividyfreitas
May 2020 | 0 Respostas
BlackShot
May 2020 | 0 Respostas
Vanessakellen
May 2020 | 0 Respostas
Guiduarter
May 2020 | 0 Respostas
Mrzaine
May 2020 | 0 Respostas
O QUE SERIA AUTONOMIA?
Grazifer
May 2020 | 0 Respostas
Joazinho
May 2020 | 0 Respostas
a palavra rapidez formou se de qual derivacao
Celiana
May 2020 | 0 Respostas
Joazinho
May 2020 | 0 Respostas
Anatercia
May 2020 | 0 Respostas
×
Report "Qual a função f (x) = a x b , cujo gráfico passa pelos pontos ( -1, 0) e (0,5)?.... Pergunta de ideia de Faelopanda"
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
Sobre nós
Política de Privacidade
Termos e Condições
direito autoral
Contate-Nos
Helpful Social
Get monthly updates
Submit
Copyright © 2024 ELIBRARY.TIPS - All rights reserved.
Lista de comentários
f (x) = ax + b
Temos:
0 = a (-1) + b (I)
5 = a (0) + b (II)
De (II)
5 = 0 + b => b = 5
levando para (I)
0 = -a + b
0 = -a + 5
-5 = -a => a = 5
Então:
f (x) = 5x + 5