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Luccamartins
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December 2019
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Qual E A Soma Dos Números Pares Compreendidos Entre 1 a 101 (a) 250 (b) 2050 (c) 2555 (d) 2550 (e) Zero
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TiagoEd
A1 = 2
an = 100
r = 2
an = a1 + (n-1) * r
100 = 2 + (n-1) * 2
100 = 2 + 2n - 2
2n = 100
n = 100 / 2
n = 50
S50 = (a1 + an) * n / 2
S50 = ( 2 + 100) * 50 / 2
S50 = 102 * 25
S50 = 2 550
Resposta: Letra D - 2 550.
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an = 100
r = 2
an = a1 + (n-1) * r
100 = 2 + (n-1) * 2
100 = 2 + 2n - 2
2n = 100
n = 100 / 2
n = 50
S50 = (a1 + an) * n / 2
S50 = ( 2 + 100) * 50 / 2
S50 = 102 * 25
S50 = 2 550
Resposta: Letra D - 2 550.