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Komodandes
@Komodandes
December 2019
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Qual é o cálculo de: 2 elevado a (4x+1) vezes 8 elevado a (-x+3) = 16 elevado a -1
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gustavobarbon01
[2^(4x+1)] × [8^(-x+3)] = 16^-1
[2^(4x+1)] × [2³^(-x+3)] = 2^-4
(4x+1) + (-3x+9) = -4
4x +1 -3x +9 = -4
x = -14
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[2^(4x+1)] × [2³^(-x+3)] = 2^-4
(4x+1) + (-3x+9) = -4
4x +1 -3x +9 = -4
x = -14