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AlaNN25
@AlaNN25
December 2019
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Qual é o volume ocupado por 14g de gás nitrogênio (N20), NAS CNTP ?
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MP39
Olá!!!.
M(N2O) = 2•14 + 16 = 44g/mol
22,4L ----------- 28g
X ----------------- 14g
X = 11,2 L
2 votes
Thanks 1
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M(N2O) = 2•14 + 16 = 44g/mol
22,4L ----------- 28g
X ----------------- 14g
X = 11,2 L