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Uendison
@Uendison
December 2019
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Qual é o zero da função afim f: IR --> IR definida por y= -12x + 20?
ME AJUDEM POR FAVOR. OBRIGADO.
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helemvargas7
Y= -12x + 20
-12x=-20
x=-20/-12
fatora por 4
x=-5/-3
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2 (y+6)=y (y-2) ME AJUDEM POR FAVOR. OBRIGADO.
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-12x=-20
x=-20/-12
fatora por 4
x=-5/-3