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Girlcrazy02
@Girlcrazy02
November 2019
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Qual o número máximo de Contagem utilizando 3 bits?
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albertrieben
Boa noite
x = 2^0 + 2^1 + 2^2 = 1 + 2 + 4 = 7
ou
x = 2^4 - 1 = 8 - 1 = 7
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x = 2^0 + 2^1 + 2^2 = 1 + 2 + 4 = 7
ou
x = 2^4 - 1 = 8 - 1 = 7