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SrtaEstranha
@SrtaEstranha
December 2019
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Quantos mols de átomos estão presentes em uma mistura contendo 7,6 gramas de KOH; 134,1 gramas de NaI e 56 gramas de CaO?
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hecstein
K = 39g/mol
Na = 23g/mol
Ca = 40g/mol
H = 1g/mol
O = 16g/mol
I = 127g/mol
--------//---------
KOH = 56g/mol
NaI = 150g/mol
CaO = 56g/mol
---------//---------
6,02×10²³ → 56g KOH
x → 7,6g KOH
♦ x = (7,6 × 6,02×10²³)÷56
x = 0,817×10²³
___________________
6,02×10²³ → 150g NaI
x → 134,1g NaI
♦x = (134,1 × 6,02×10²³)÷150
x = 5,38×10²³
___________________
6,02×10²³ → 56g CaO
x → 56g CaO
♦x = (56 × 6,02×10²³)÷56
x = 6,02×10²³
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Na = 23g/mol
Ca = 40g/mol
H = 1g/mol
O = 16g/mol
I = 127g/mol
--------//---------
KOH = 56g/mol
NaI = 150g/mol
CaO = 56g/mol
---------//---------
6,02×10²³ → 56g KOH
x → 7,6g KOH
♦ x = (7,6 × 6,02×10²³)÷56
x = 0,817×10²³
___________________
6,02×10²³ → 150g NaI
x → 134,1g NaI
♦x = (134,1 × 6,02×10²³)÷150
x = 5,38×10²³
___________________
6,02×10²³ → 56g CaO
x → 56g CaO
♦x = (56 × 6,02×10²³)÷56
x = 6,02×10²³