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Lorenamor
@Lorenamor
September 2019
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Quantos numeros ímpares de 6 algarismos podemos escrever usando os algarismos 3,3,1,1,4 e 6 respeitando as repetições apresentadas? R: 120
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A=3
b=1
c=4
d=6
aabbcd
final a
anagrama ==> 5*4*3*2*1*2/2!2! =60
final b
anagrama ==> 5*4*3*2*1*2/2!2! =60
soma=60+60=120
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b=1
c=4
d=6
aabbcd
final a
anagrama ==> 5*4*3*2*1*2/2!2! =60
final b
anagrama ==> 5*4*3*2*1*2/2!2! =60
soma=60+60=120