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Victorismoura
@Victorismoura
October 2019
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Quantos termos tem uma P.G (3,6,12,...,3072)?
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adryflor80
Q=6/3=2
3072=a1*q^n-1
3072=3*2^n-1
3072/3=2^n-1
1024=2^n-1
2^^10=2^n-1
n-1=10
n=10+1
n=11
são 11 termos
1 votes
Thanks 1
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3072=a1*q^n-1
3072=3*2^n-1
3072/3=2^n-1
1024=2^n-1
2^^10=2^n-1
n-1=10
n=10+1
n=11
são 11 termos