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Barbarapg123
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January 2020
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Que volume em litros de uma solução aquosa 1,5M de Ca(OH)2 pode-se preparar com 35,7g desta base?(Ca=40;O=16;H=1)
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WillQuimica
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* Massa molar Ca(OH)2 = 40 + 16 x 2 + 1 x 2 => 74 g/mol
Número de mols do soluto :
1 mol Ca(OH)2 ------------------------- 74 g
n mol Ca(OH)2 ------------------------- 35,7 g
n = 35,7 / 74
n = 0,482 mols
Por fim o volume será de :
1 L --------------- 1,5 mols
V ----------------- 0,482 mols
V = 0,482 / 1,5
V = 0,321 L
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Verified answer
* Massa molar Ca(OH)2 = 40 + 16 x 2 + 1 x 2 => 74 g/molNúmero de mols do soluto :
1 mol Ca(OH)2 ------------------------- 74 g
n mol Ca(OH)2 ------------------------- 35,7 g
n = 35,7 / 74
n = 0,482 mols
Por fim o volume será de :
1 L --------------- 1,5 mols
V ----------------- 0,482 mols
V = 0,482 / 1,5
V = 0,321 L
Att ...