Articles
Register
Sign In
Search
Brunosouza203
@Brunosouza203
December 2019
1
88
Report
Raizes e vértice da função 2x.(5-x)=x²+3
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms and service
You must agree before submitting.
Send
Lista de comentários
walacebarros
F(x) = 2x(5-x)=x²+3
f(x) = 10x - 2x²=x²+3
f(x) = 10x -2x²-x²-3=0
f(x) = -3x²+10x-3=0
coeficientes
A= -3
B= 10
C= -3
Jogando os coeficientes na formula de bhaskara, iremos encontrar as raízes da função:
x1= 3
x2= 1/3
Interseção com o eixo y = -3(0)²+10(0) -3
y = -3
vértice
xv= -b/2a
xv= 5/3
yv= -Δ/4a Δ=b²-4ac Δ=64
yv= -(64)/4(-3)
yv= 16/3
1 votes
Thanks 0
More Questions From This User
See All
brunosouza203
December 2022 | 0 Respostas
Responda
brunosouza203
July 2022 | 0 Respostas
Responda
brunosouza203
February 2021 | 0 Respostas
Responda
Brunosouza203
December 2019 | 0 Respostas
Responda
Brunosouza203
December 2019 | 0 Respostas
Responda
Brunosouza203
December 2019 | 0 Respostas
Responda
Brunosouza203
December 2019 | 0 Respostas
Responda
Brunosouza203
December 2019 | 0 Respostas
Responda
Brunosouza203
December 2019 | 0 Respostas
Responda
Brunosouza203
December 2019 | 0 Respostas
Responda
Recomendar perguntas
Deividyfreitas
May 2020 | 0 Respostas
BlackShot
May 2020 | 0 Respostas
Vanessakellen
May 2020 | 0 Respostas
Guiduarter
May 2020 | 0 Respostas
Mrzaine
May 2020 | 0 Respostas
O QUE SERIA AUTONOMIA?
Grazifer
May 2020 | 0 Respostas
Joazinho
May 2020 | 0 Respostas
a palavra rapidez formou se de qual derivacao
Celiana
May 2020 | 0 Respostas
Joazinho
May 2020 | 0 Respostas
Anatercia
May 2020 | 0 Respostas
×
Report "Raizes e vértice da função 2x.(5-x)=x²+3.... Pergunta de ideia de Brunosouza203"
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
Sobre nós
Política de Privacidade
Termos e Condições
direito autoral
Contate-Nos
Helpful Social
Get monthly updates
Submit
Copyright © 2024 ELIBRARY.TIPS - All rights reserved.
Lista de comentários
f(x) = 10x - 2x²=x²+3
f(x) = 10x -2x²-x²-3=0
f(x) = -3x²+10x-3=0
coeficientes
A= -3
B= 10
C= -3
Jogando os coeficientes na formula de bhaskara, iremos encontrar as raízes da função:
x1= 3
x2= 1/3
Interseção com o eixo y = -3(0)²+10(0) -3
y = -3
vértice
xv= -b/2a
xv= 5/3
yv= -Δ/4a Δ=b²-4ac Δ=64
yv= -(64)/4(-3)
yv= 16/3