a)
b)
c)
d)
e)
a) \frac{\sqrt{15}}{\sqrt3} = \frac{{\sqrt5}\cdot{\sqrt3}}{\sqrt3}[/tex]
simplificando temos
simplificando temos:
simplificando, temos:
Copyright © 2025 ELIBRARY.TIPS - All rights reserved.
Lista de comentários
a)
b)
c)
d)
e)
a) \frac{\sqrt{15}}{\sqrt3} = \frac{{\sqrt5}\cdot{\sqrt3}}{\sqrt3}[/tex]
simplificando temos
b)
simplificando temos:
c)
simplificando, temos:
d)![\sqrt[3]{2} \cdot \sqrt2 = \sqrt[6]{2}</p> <p> </p> <p>e) \[tex]\frac{\sqrt[3]{4}}{\sqrt2} = \frac{\sqrt[3]{2^2}}{\sqrt2} \sqrt[3]{2} \cdot \sqrt2 = \sqrt[6]{2}</p> <p> </p> <p>e) \[tex]\frac{\sqrt[3]{4}}{\sqrt2} = \frac{\sqrt[3]{2^2}}{\sqrt2}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B2%7D%20%5Ccdot%20%5Csqrt2%20%3D%20%5Csqrt%5B6%5D%7B2%7D%3C%2Fp%3E%0A%3Cp%3E%20%3C%2Fp%3E%0A%3Cp%3Ee%29%20%20%20%5C%5Btex%5D%5Cfrac%7B%5Csqrt%5B3%5D%7B4%7D%7D%7B%5Csqrt2%7D%20%3D%20%5Cfrac%7B%5Csqrt%5B3%5D%7B2%5E2%7D%7D%7B%5Csqrt2%7D)
simplificando, temos:![2^\frac16 = \sqrt[6]{2} 2^\frac16 = \sqrt[6]{2}](https://tex.z-dn.net/?f=2%5E%5Cfrac16%20%3D%20%5Csqrt%5B6%5D%7B2%7D)