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Italocau
@Italocau
September 2019
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Reponda : 3x^2-11x+10x=0
(FORMULA DE BHASKARA)
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srjonylima
3x²-11x+10x=0
3x²-1x=0
Δ=b²-4ac
Δ=(-1)²-4*3*0
Δ=1
x1= -b+raíz de delta
x1= -(-1) + 1
x1= +2
x2= -b -raiz de delta
x2= -(-1) -1
x2= 0
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3x²-1x=0
Δ=b²-4ac
Δ=(-1)²-4*3*0
Δ=1
x1= -b+raíz de delta
x1= -(-1) + 1
x1= +2
x2= -b -raiz de delta
x2= -(-1) -1
x2= 0