Resolva: (4^x)^x-1=16.... Pergunta de ideia deJohannwieth

October 2019 1 32 Report

Resolva:
(4^x)^x-1=16

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brunnaborges15 4x+x²-1=16
4x+x²-1-16=0
4x+x²-17=0
x=-b±√-4ac/2a
x=-4±√-4.1.(-17)/2.1
x=-4±√68/2
x=-4±8,24/2
x1=-4+8,24/2
x1= 4,24/2
x1= 2,12
X2=-4-8,24/2
X2=-12,24/2
X2= -6,12

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