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Brainly13
@Brainly13
December 2019
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Resolva a equação (n+2)! = 15 . (n+1)! - (n+3)!
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lelunardi1
(n+2)! = 15.(n=1)! - (n+3)!
(n+2)!! = 15.(n+1)! - (n+3)(n+2)(n+1)!
(n+2)(n+1)! = (n+1)!(15-(n+3)(n+2))
n+2 =15 - (n+3)(n+2)
n+2 = 15 - (n² +5n +6)
n+2 = 15 -n² -5n -6
n +2 -9 +n² +5n = 0
n² +6n -7 = 0
(n+7)(n-1) = 0
n' = -7 ou n'' = 1
0 votes
Thanks 0
lelunardi1
o que é esse sinal de exclamação???
lelunardi1
desculpe... pensei que não fosse nada...
lelunardi1
está aí...
lelunardi1
: )
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(n+2)!! = 15.(n+1)! - (n+3)(n+2)(n+1)!
(n+2)(n+1)! = (n+1)!(15-(n+3)(n+2))
n+2 =15 - (n+3)(n+2)
n+2 = 15 - (n² +5n +6)
n+2 = 15 -n² -5n -6
n +2 -9 +n² +5n = 0
n² +6n -7 = 0
(n+7)(n-1) = 0
n' = -7 ou n'' = 1