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Jljjunior
@Jljjunior
October 2019
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Resolva a inequação:
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Rich0031
(1 - x)(4 + x)/5 - 3x ≥ 0
(1 - x)(4 + x) ≥ 0
- x² - 3x + 4 ≥ 0
x² + 3x - 4 ≤ 0
x² + 3x - 4 = 0
x1 + x2 = - b/a
x1 + x2 = - 3 (1 - 4)
x1 . x2 = c/a
x1 . x2 = - 4 [(1.(-4)]
S = {x € R | - 4 ≤ x ≤ 1}
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Lista de comentários
(1 - x)(4 + x) ≥ 0
- x² - 3x + 4 ≥ 0
x² + 3x - 4 ≤ 0
x² + 3x - 4 = 0
x1 + x2 = - b/a
x1 + x2 = - 3 (1 - 4)
x1 . x2 = c/a
x1 . x2 = - 4 [(1.(-4)]
S = {x € R | - 4 ≤ x ≤ 1}