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LiahHale
@LiahHale
September 2019
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Resolva a questão a seguir:
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vitorjoaoaoao
A₁₁= cos1π= -1 a₁₂=sen1π= 0
a₂₁= cos2π= 1 a₂₂=cos2π= 1
a₃₁= cos3π= -1 a₃₂=cos3π= -1
a) A=
b) A
=
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Lista de comentários
a₂₁= cos2π= 1 a₂₂=cos2π= 1
a₃₁= cos3π= -1 a₃₂=cos3π= -1
a) A=
b) A=