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Zezar
@Zezar
December 2019
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Resolva em C, a equação x²-2x+17=0.
a) S= {1+i,1-i}
b) S= {1+2i, 1-2i}
c) S= {1+3i, 1-3i}
d) S= {1+4i, 1-4i}
e) S={1+5i, 1-5i}
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A=1 b=-2 c=17
Δ=(-2)²-4.1.17 x=2+-√-64i/2
Δ=4-68
Δ=-64i x1=2+8i/2 = 1+4i
x2=2-8i/2=1-4 i,letra d
1 votes
Thanks 1
lugano1
A = 1
b = -2
c = 17
b*=-4.a.c
(-2)*-4.1.17.. todo num -.elev a exp fica +
4-68...d =64...x€R >0..
-b+-Vd/2a
-(-2)+-V64/2.1
2+-8/2
x'...2+8/2...x' = 4
x" 2-8/2...x" = -4
resposta letra D...S=1+4i, 1-4i
0 votes
Thanks 0
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Δ=(-2)²-4.1.17 x=2+-√-64i/2
Δ=4-68
Δ=-64i x1=2+8i/2 = 1+4i
x2=2-8i/2=1-4 i,letra d
b = -2
c = 17
b*=-4.a.c
(-2)*-4.1.17.. todo num -.elev a exp fica +
4-68...d =64...x€R >0..
-b+-Vd/2a
-(-2)+-V64/2.1
2+-8/2
x'...2+8/2...x' = 4
x" 2-8/2...x" = -4
resposta letra D...S=1+4i, 1-4i