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Maya2016
@Maya2016
December 2019
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Resolva:
a) (x-3)^2=2x^2
b) X(x-5)=-6
c) X(3x+4)= -1
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ribeiromila
A) (x-3) ²= 2x²
(x-3) (x-3)
x²-3x-3x+9= 4x²
x²-6x+9= 4x²
-3x²-6x+9= 0
Faz baskára
b²-4ac
(-6)²-4(-3)(9)
36+108
Δ= 144
-b√Δ/ 2a
-(-6)+- 12/ 2(-3)
6+-12/-6
X¹= -3 X²= 1
b) x² - 5x= -6
x²-5x+6=0
Faz baskara de novo dando X¹= 3 e X²= 2
c) 3x²+ 4x+ -1
3x²+4x+1=0
Faz baskara dando
X¹= -4+7√2÷ 6 e X²= -4-7√2÷6
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Lista de comentários
(x-3) (x-3)
x²-3x-3x+9= 4x²
x²-6x+9= 4x²
-3x²-6x+9= 0
Faz baskára
b²-4ac
(-6)²-4(-3)(9)
36+108
Δ= 144
-b√Δ/ 2a
-(-6)+- 12/ 2(-3)
6+-12/-6
X¹= -3 X²= 1
b) x² - 5x= -6
x²-5x+6=0
Faz baskara de novo dando X¹= 3 e X²= 2
c) 3x²+ 4x+ -1
3x²+4x+1=0
Faz baskara dando X¹= -4+7√2÷ 6 e X²= -4-7√2÷6