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Karolcj20
@Karolcj20
December 2019
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Se a reta da equação (2+k) x + (k-3) y+ 2=0 passa pelo ponto P (2,3), entao o valor de k é:
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BetShammah
P(2,3)
x = 2
y = 3
(2 + k)x + (k - 3)y + 2 = 0
(2 + k).2 + (k - 3)3 + 2 = 0
4 + 2k + 3k - 9 + 2 = 0
4 + 5k - 7 = 0
5k = 7 - 4
5k = 3
k = 3/5
Resposta: k = 3/5
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Lista de comentários
x = 2
y = 3
(2 + k)x + (k - 3)y + 2 = 0
(2 + k).2 + (k - 3)3 + 2 = 0
4 + 2k + 3k - 9 + 2 = 0
4 + 5k - 7 = 0
5k = 7 - 4
5k = 3
k = 3/5
Resposta: k = 3/5