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Constanciamaria
@Constanciamaria
April 2020
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Seja f: R - R a união definida por f(x) = -3x + 3. Determine o valor de f(1) - f(-2) + f(3).
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wandersonoliveira
Verified answer
F(1)=-3.1+3
f(1)=-3+3
f(1)=0
f(-2)=-3.(-2)+3
f(-2)=6+3
f(-2)=9
f(-3)=-3.3+3
f(3)=-9+3
f(3)=-6
f(1)-f(-2)+f(3)
0-9+(-6)
-9-6
-15
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3478elc
f(x) = - 3x + 3
f(1) - f(-2) + f(3) = 0 - 9 - 6 ==>
3
f(1) = - 3(1) + 3 = - 3 + 3 = 0
f(-2) = - 3(-2) + 3= 6 + 3 = 9
f(3) = - 3(3) + 3 = - 9 + 3 = - 6
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Verified answer
F(1)=-3.1+3f(1)=-3+3
f(1)=0
f(-2)=-3.(-2)+3
f(-2)=6+3
f(-2)=9
f(-3)=-3.3+3
f(3)=-9+3
f(3)=-6
f(1)-f(-2)+f(3)
0-9+(-6)
-9-6
-15
f(1) - f(-2) + f(3) = 0 - 9 - 6 ==> 3
f(1) = - 3(1) + 3 = - 3 + 3 = 0
f(-2) = - 3(-2) + 3= 6 + 3 = 9
f(3) = - 3(3) + 3 = - 9 + 3 = - 6