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MariaEduardaCABRITA
@MariaEduardaCABRITA
January 2020
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Sendo log2=0;3010 e log3=0,4771 ,o valor mais próximo de lograizde216 é?
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ProfRafael
Dados:
log 2 = 0,3010
log 3 = 0,4771
Pede-se: log √216
log √216 = log √6³ = log 6^(3/2) = (3/2).log 6
(3/2).log 6 = (3/2)(log 2.3) = (3/2)(log 2 + log 3)
(3/2)(0,3010 + 0,4771) = (3/2)(0,7781) = 2,3343/2 = 1,16715
Resposta: log √216 = 1,16715
Espero ter ajudado.
2 votes
Thanks 2
ProfRafael
Obrigado!
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Lista de comentários
log 2 = 0,3010
log 3 = 0,4771
Pede-se: log √216
log √216 = log √6³ = log 6^(3/2) = (3/2).log 6
(3/2).log 6 = (3/2)(log 2.3) = (3/2)(log 2 + log 3)
(3/2)(0,3010 + 0,4771) = (3/2)(0,7781) = 2,3343/2 = 1,16715
Resposta: log √216 = 1,16715
Espero ter ajudado.