(x + 2, y - 3) = ( 2x + 1 , 3y - 1)
x + 2 = 2x + 1
2 - 1 = 2x - x
1 = x
x = 1
y - 3 = 3y - 1
- 3 + 1 = 3y - y
- 2 = 2y
2y = - 2
y = -2/2
y = - 1
= x + y
= 1 - 1
= 0
R.: 0
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(x + 2, y - 3) = ( 2x + 1 , 3y - 1)
x + 2 = 2x + 1
2 - 1 = 2x - x
1 = x
x = 1
y - 3 = 3y - 1
- 3 + 1 = 3y - y
- 2 = 2y
2y = - 2
y = -2/2
y = - 1
= x + y
= 1 - 1
= 0
R.: 0