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2016Thiago
@2016Thiago
January 2020
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Supondo que α (alfa) é um angulo agudo e que cos α (alfa)=
, calcule sen α (alfa) e tg α (alfa).
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felipecamposolv
Sen²
α + (2/3)²=1
sen²
α = 1-4/9
sen²
α = 5/9
sen²
α= + ou - √5/9
sen²
α= 5/3
tg α = 5/3 ÷ 2/3
tg α = 5/2
1 votes
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sen² α = 1-4/9
sen² α = 5/9
sen² α= + ou - √5/9
sen² α= 5/3
tg α = 5/3 ÷ 2/3
tg α = 5/2