Ta escrito a soma dos 25 primeiros termos da p.a (-15,-11,-7,).... Pergunta de ideia deReenatiinha2017

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Ta escrito a soma dos 25 primeiros termos da p.a (-15,-11,-7,)

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Rich0031 R = a2 - a1
r = - 11 + 15 = 4

$a_2_5 = a_1 + 24r \\ a_2_5 = - 15 + 24.4 = - 15 + 96 = 81 \\ \\ S_2_5 = \frac{(- 15 + 81).25}{2} \\ \\ S_2_5 = \frac{\cancel{66}.25}{\cancel{2}} = 33.25 = 825$

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