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Nox113
@Nox113
December 2019
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Teorema de Pitágoras calcule o valor de x nos triângulos retângulos.
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(2x)²=(3√3)²+x²
4x²=(3²*3)+x²
4x²-x²=27
3x²=27
x²=27/3
x²=9
x=√9
x=3
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4x²=(3²*3)+x²
4x²-x²=27
3x²=27
x²=27/3
x²=9
x=√9
x=3