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Edusilvap
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August 2019
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Triangulo semelhante, calculaaaar
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araujofranca
A FIGURA MOSTRA QUE OS TRIÂNGULOS ACB e ADE SÃO SE-
MELHANTES (DOIS ÂNGULOS COMUNS: A=A e C=D)
ENTÃO: AC / AD = AB / AE
18 / 6 = 9 / y
3 / 1 = 9 / y
3 . y = 9
y = 9 : 3, y = 3
AC / AD = BC / ED
3 / 1 = 10 / x
3 . x = 10
x = 10/3, x ~= 3,33
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Edusilvap
socorro mto obg, vc ta me salvando t amo
araujofranca
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Lista de comentários
A FIGURA MOSTRA QUE OS TRIÂNGULOS ACB e ADE SÃO SE-
MELHANTES (DOIS ÂNGULOS COMUNS: A=A e C=D)
ENTÃO: AC / AD = AB / AE
18 / 6 = 9 / y
3 / 1 = 9 / y
3 . y = 9
y = 9 : 3, y = 3
AC / AD = BC / ED
3 / 1 = 10 / x
3 . x = 10
x = 10/3, x ~= 3,33