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CassioRF
@CassioRF
November 2019
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Um copo de massa igual a 1kg recebeu 10kcal e sua temperatura passou de 50°c para 100°c qual é o calor específico desse copo?
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isabelahhh1
C=Q/m.T
c=10000/1000.50
c=0.20cal/g.°C
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c=10000/1000.50
c=0.20cal/g.°C