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Kevys
@Kevys
April 2019
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Um poligono convexo tem 9 diagonais. O numero de lados é?
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rbgrijo2011
D = 9
n(n-3)/2 = 9
n² -3n -18 = 0 => a=1, b=-3, c=-18
∆=b²-4ac= 9+72=81 => √∆=9
n = -b±√∆/2a
n' = 3+9/2 = 12/2 = 6 lados ✓
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Lista de comentários
n(n-3)/2 = 9
n² -3n -18 = 0 => a=1, b=-3, c=-18
∆=b²-4ac= 9+72=81 => √∆=9
n = -b±√∆/2a
n' = 3+9/2 = 12/2 = 6 lados ✓