POR COMPARAÇÃO:
(100-0)/(C-0)=[(120-(-20)]/[X -(-20)]
100/C=[120+20]/[X+20]
100/C=[140]/[X+20]
100[X+20]=140C
5[X+20]=7C
C=5[X+20]/7
Para: X=C
x=5[X+20]/7
7X=5[X+20]
7X=5X+100
7X-5X=100
2X=100
X=100/2
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POR COMPARAÇÃO:
(100-0)/(C-0)=[(120-(-20)]/[X -(-20)]
100/C=[120+20]/[X+20]
100/C=[140]/[X+20]
100[X+20]=140C
5[X+20]=7C
C=5[X+20]/7
Para: X=C
x=5[X+20]/7
7X=5[X+20]
7X=5X+100
7X-5X=100
2X=100
X=100/2
X=50º
Resposta: 50º