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Kauanvunu
@Kauanvunu
December 2019
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URGENTE
Me ajudem nessas 2 equações biquadradas por favor com conta completa
A)16x^4 - 40x² +9 =0
B)x^4 -7x² +12 =0
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DanielS6
A)
16x⁴ - 40x² + 9 = 0 x² = y
16y² - 40y + 9 = 0
a = 16, b = - 40, c = 9
Δ = b² - 4ac
Δ = (- 40)² - 4 . 16 . 9
Δ = 1600 - 576
Δ = 1024
Δ = 32²
y = (- b ± √Δ)/2a
y = (- (- 40) ± √32²)/2 . 16
y = (40 ± 32)/32
y = 5/4 ± 1
y' = 5/4 + 1 = 9/4
y'' = 5/4 - 1 = 1/4
x² = y → x = ± √y
x' = ± √(9/4) = ± 3/2
x'' = ± √(1/4) = ± 1/2
S = {3/2, - 3/2, 1/2, - 1/2}
b)
x⁴ - 7x² + 12 = 0 x² = y
y² - 7y + 12 = 0
a = 1, b = - 7, c = 12
Δ = b² - 4ac
Δ = (- 7)² - 4 . 1 . 12
Δ = 49 - 48
Δ = 1
x = (- b ± √Δ)/2a
x = (- (- 7) ± √1)/2 . 1
x = (7 ± 1)/2
x' = (7 + 1)/2 = 8/2 = 4
x'' = (7 - 1)/2 = 6/2 = 3
x² = y → x = ± √y
x = ± √4 = ± 2
x = ± √3
S = {2, - 2, √3, - √3}
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Lista de comentários
16x⁴ - 40x² + 9 = 0 x² = y
16y² - 40y + 9 = 0
a = 16, b = - 40, c = 9
Δ = b² - 4ac
Δ = (- 40)² - 4 . 16 . 9
Δ = 1600 - 576
Δ = 1024
Δ = 32²
y = (- b ± √Δ)/2a
y = (- (- 40) ± √32²)/2 . 16
y = (40 ± 32)/32
y = 5/4 ± 1
y' = 5/4 + 1 = 9/4
y'' = 5/4 - 1 = 1/4
x² = y → x = ± √y
x' = ± √(9/4) = ± 3/2
x'' = ± √(1/4) = ± 1/2
S = {3/2, - 3/2, 1/2, - 1/2}
b)
x⁴ - 7x² + 12 = 0 x² = y
y² - 7y + 12 = 0
a = 1, b = - 7, c = 12
Δ = b² - 4ac
Δ = (- 7)² - 4 . 1 . 12
Δ = 49 - 48
Δ = 1
x = (- b ± √Δ)/2a
x = (- (- 7) ± √1)/2 . 1
x = (7 ± 1)/2
x' = (7 + 1)/2 = 8/2 = 4
x'' = (7 - 1)/2 = 6/2 = 3
x² = y → x = ± √y
x = ± √4 = ± 2
x = ± √3
S = {2, - 2, √3, - √3}