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Junior1818
@Junior1818
November 2019
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X²-5x+6=0 determine o valor de delta e de x.
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Nymph
A = 1
b = - 5
c = 6
Δ = b² - 4.a.c
Δ = (-5)² - 4.1.6
Δ = 25 - 24
Δ = 1
x' = - b + √Δ/2a
x' = -(-5) + 1/2
x' = 5 + 1/2
x' = 6/2 = 3
x'' = - b - √Δ/2a
x'' = -(-5) - 1/2
x'' = 5 - 1/2
x'' = 4/2
x'' = 2
Δ = 1
x' = 3
x'' = 2
1 votes
Thanks 5
exalunosp
X² - 5x + 6 = 0
a = 1
b = -5
c = +6
b² - 4ac = (-5)² - [ 4 * 1 * 6 ] = 25 - 24 = 1 ou +-V1 = +-1 ***
x = ( 5 +-1)/2
x1 = 6/2 = 3 *****
x2 = 4/2 = 2 *****
resposta 3 e 2 ***
0 votes
Thanks 1
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Lista de comentários
b = - 5
c = 6
Δ = b² - 4.a.c
Δ = (-5)² - 4.1.6
Δ = 25 - 24
Δ = 1
x' = - b + √Δ/2a
x' = -(-5) + 1/2
x' = 5 + 1/2
x' = 6/2 = 3
x'' = - b - √Δ/2a
x'' = -(-5) - 1/2
x'' = 5 - 1/2
x'' = 4/2
x'' = 2
Δ = 1
x' = 3
x'' = 2
a = 1
b = -5
c = +6
b² - 4ac = (-5)² - [ 4 * 1 * 6 ] = 25 - 24 = 1 ou +-V1 = +-1 ***
x = ( 5 +-1)/2
x1 = 6/2 = 3 *****
x2 = 4/2 = 2 *****
resposta 3 e 2 ***