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AndrewsVN
@AndrewsVN
January 2020
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X e Y do vertice de F(x) 9x-x²
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nimbus
Xv=-(b/2a)
Xv=-(9/-2)
Xv=4,5
Yv=-(delta/4a) delta=81 -4*-1*0
Yv=-(81/-4) delta= 81
Yv=20,25
R=(4.5,20.25)
2 votes
Thanks 1
jgfernog
Xv = -b / 2a
Yv = -Δ/4a
Vamos achar o delta antes:
Δ = b² - 4.a.c
Δ= 81 - 4.1.0
Δ= 81
Yv = -81 /4.-1 = -81/-4
Yv = 20,25
Xv = -9/2.-1
Xv = -9/-2
Xv = 4,5
Espero ter ajudado!
0 votes
Thanks 1
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Lista de comentários
Xv=-(9/-2)
Xv=4,5
Yv=-(delta/4a) delta=81 -4*-1*0
Yv=-(81/-4) delta= 81
Yv=20,25
R=(4.5,20.25)
Yv = -Δ/4a
Vamos achar o delta antes:
Δ = b² - 4.a.c
Δ= 81 - 4.1.0
Δ= 81
Yv = -81 /4.-1 = -81/-4
Yv = 20,25
Xv = -9/2.-1
Xv = -9/-2
Xv = 4,5
Espero ter ajudado!