(x+1)²=4x+4 pfvrrr urgenteee.... Pergunta de ideia deHellerZanchii

HellerZanchii @HellerZanchii

December 2019 1 46 Report

(x+1)²=4x+4 pfvrrr urgenteee

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Verkylen Olá!

$(x+1)^2=4x+4\\\\(x+1)(x+1)=4x+4\\\\x^2+x+x+1^2=4x+4\\\\x^2+2x+1=4x+4\\\\x^2+2x-4x+1-4=0\\\\x^2-2x-3=0\\\\x=\dfrac{-(-2)\pm\sqrt{(-2)^2-4.(1).(-3)}}{2.(1)}\\\\x=\dfrac{2\pm\sqrt{16}}{2}\\\\x=\dfrac{2\pm4}{2}\left\langle\begin{array}{lll}x=3\\\\x=-1\end{array}\right\\\\\\\boxed{\boxed{S=\{-1,\,3\}}}$

Bons estudos!

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