O oitavo termo da Progressão Geométrica:
[tex]\large \text {$\Rightarrow ~a8 = \dfrac{1}{16807} $}[/tex]
[tex]\Large\text{$ Progress\tilde{a}o ~Geom\acute{e}trica $}[/tex]
Encontrar a razão da PG.
[tex]\large \text {$ q = \dfrac{a2}{a1} $}\\\\\\\large \text {$q = \dfrac{7}{49} $}\\\\\\\large \text {$q = \dfrac{1}{7} $}\\\\[/tex]
Com o valor da razão e o valor do primeiro termo, encontrar o valor do termo a8, ( oitavo termo da PG ).
[tex]\large \text {$an = a1 ~. ~q^{n - 1} $}\\\\\\\large \text {$a8 = 49 ~. ~(\dfrac{1}{7})^{8 - 1} $}\\\\\\\large \text {$a8 = 49 ~. ~(\dfrac{1}{7})^{7} $}\\\\\\\large \text {$a8 = 49 ~. ~\dfrac{1}{823543} $}\\\\\\\large \text {$a8 = \dfrac{49}{823543} $}\\\\\\\large \text {$a8 = \dfrac{1}{16807} $}\\\\\\[/tex]
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Para saber mais:
https://brainly.com.br/tarefa/48629556
https://brainly.com.br/tarefa/51203261
https://brainly.com.br/tarefa/51220509
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O oitavo termo da Progressão Geométrica:
[tex]\large \text {$\Rightarrow ~a8 = \dfrac{1}{16807} $}[/tex]
[tex]\Large\text{$ Progress\tilde{a}o ~Geom\acute{e}trica $}[/tex]
Encontrar a razão da PG.
[tex]\large \text {$ q = \dfrac{a2}{a1} $}\\\\\\\large \text {$q = \dfrac{7}{49} $}\\\\\\\large \text {$q = \dfrac{1}{7} $}\\\\[/tex]
Com o valor da razão e o valor do primeiro termo, encontrar o valor do termo a8, ( oitavo termo da PG ).
[tex]\large \text {$an = a1 ~. ~q^{n - 1} $}\\\\\\\large \text {$a8 = 49 ~. ~(\dfrac{1}{7})^{8 - 1} $}\\\\\\\large \text {$a8 = 49 ~. ~(\dfrac{1}{7})^{7} $}\\\\\\\large \text {$a8 = 49 ~. ~\dfrac{1}{823543} $}\\\\\\\large \text {$a8 = \dfrac{49}{823543} $}\\\\\\\large \text {$a8 = \dfrac{1}{16807} $}\\\\\\[/tex]
===
Para saber mais:
https://brainly.com.br/tarefa/48629556
https://brainly.com.br/tarefa/51203261
https://brainly.com.br/tarefa/51220509