Articles
Register
Sign In
Search
KamyllaPortella0809
@KamyllaPortella0809
December 2019
1
59
Report
Sendo cosx= 2/3, com 3 pi/2 < x< 2 pi determinar a cotgx e cossecanx
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms and service
You must agree before submitting.
Send
Lista de comentários
GeniusMaia
Olá,
A cotgx = cosx/senx. Temos cosx, mas não temos senx. Vamos encontrá-lo:
sen²x + cos²x = 1
sen²x + (2/3)² = 1
sen²x = 1 - 4/9
sen²x = 5/9
senx = √5/3
cotgx = cosx/senx
cotgx = (2/3)/(√5/3)
cotgx = (2/3)*(3√5)
cotgx = 6/3√5
cotgx = 2/√5
cotgx = 2√5/5
cossecx = 1/senx
cossecx = 1/(√5/3)
cossecx = 1*3/√5
cossecx = 3/√5
cossecx = 3√5/5
Bons estudos ;)
2 votes
Thanks 3
More Questions From This User
See All
KamyllaPortella0809
December 2019 | 0 Respostas
Sendo senx=-3/4, com pi
Responda
KamyllaPortella0809
December 2019 | 0 Respostas
Sendo senx=-3/4, com pi < x< 3 pi/2 determinar tgx e secantx
Responda
KamyllaPortella0809
December 2019 | 0 Respostas
Responda
KamyllaPortella0809
December 2019 | 0 Respostas
Responda
KamyllaPortella0809
December 2019 | 0 Respostas
Responda
KamyllaPortella0809
October 2019 | 0 Respostas
Responda
KamyllaPortella0809
October 2019 | 0 Respostas
Responda
Recomendar perguntas
Deividyfreitas
May 2020 | 0 Respostas
BlackShot
May 2020 | 0 Respostas
Vanessakellen
May 2020 | 0 Respostas
Guiduarter
May 2020 | 0 Respostas
Mrzaine
May 2020 | 0 Respostas
O QUE SERIA AUTONOMIA?
Grazifer
May 2020 | 0 Respostas
Joazinho
May 2020 | 0 Respostas
a palavra rapidez formou se de qual derivacao
Celiana
May 2020 | 0 Respostas
Joazinho
May 2020 | 0 Respostas
Anatercia
May 2020 | 0 Respostas
×
Report "Sendo cosx= 2/3, com 3 pi/2 < x< 2 pi determinar a cotgx e cossecanx.... Pergunta de ideia de KamyllaPortella0809"
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
Sobre nós
Política de Privacidade
Termos e Condições
direito autoral
Contate-Nos
Helpful Social
Get monthly updates
Submit
Copyright © 2024 ELIBRARY.TIPS - All rights reserved.
Lista de comentários
A cotgx = cosx/senx. Temos cosx, mas não temos senx. Vamos encontrá-lo:
sen²x + cos²x = 1
sen²x + (2/3)² = 1
sen²x = 1 - 4/9
sen²x = 5/9
senx = √5/3
cotgx = cosx/senx
cotgx = (2/3)/(√5/3)
cotgx = (2/3)*(3√5)
cotgx = 6/3√5
cotgx = 2/√5
cotgx = 2√5/5
cossecx = 1/senx
cossecx = 1/(√5/3)
cossecx = 1*3/√5
cossecx = 3/√5
cossecx = 3√5/5
Bons estudos ;)