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LuccasEstudos2017
@LuccasEstudos2017
January 2020
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Sobre exponencial:
6x(2/3)^x²-16x+72=3072/19683 --> Resposta={7,9}
3^x-1 + 3^x + 3^x+1=351 --> Resposta=4
4^3x-1 + 4^x=4^2x --> Resposta=1/2
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spnatwn
6*(2/3)^x²-16x+72=3072/19683
6*(2/3)^x²-16x+72=6*512/19683
(2/3)^x²-16x+72=512/19683
(2/3)^x²-16x+72=(2/3)^9
x²-16x+72=9
x²-16x+63=0
S=16 P=63
x'=7 x''=9
4^3x-1 + 4^x=4^2x
4^3x/4+4^x-4^2x=0
4^3x+4*4^x-4*4^2x=0
4^x=y
y³+4y-4y²=0
y(y²+4-4y)=0
y=0 > não serve
y²-4y+4=0
S=4 P=4
x'=2 x''=2
4^x=2
2^2x=2^1
2x=1
x=1/2
3^x-1 + 3^x + 3^x+1=351
3^x/3+3^x*3=351
3^x+3*3^x+3*3*3^x=351
3^x=y
y+12y=1053
13y=1053
y=81
3^x=81
3^x=3^4
x=4
2 votes
Thanks 1
LuccasEstudos2017
Obrigado !!
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6*(2/3)^x²-16x+72=6*512/19683
(2/3)^x²-16x+72=512/19683
(2/3)^x²-16x+72=(2/3)^9
x²-16x+72=9
x²-16x+63=0
S=16 P=63
x'=7 x''=9
4^3x-1 + 4^x=4^2x
4^3x/4+4^x-4^2x=0
4^3x+4*4^x-4*4^2x=0
4^x=y
y³+4y-4y²=0
y(y²+4-4y)=0
y=0 > não serve
y²-4y+4=0
S=4 P=4
x'=2 x''=2
4^x=2
2^2x=2^1
2x=1
x=1/2
3^x-1 + 3^x + 3^x+1=351
3^x/3+3^x*3=351
3^x+3*3^x+3*3*3^x=351
3^x=y
y+12y=1053
13y=1053
y=81
3^x=81
3^x=3^4
x=4