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Lisaah
@Lisaah
April 2020
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Dada a funçao f: R ⇒R definida por f(x) = 3x + 1 , calcule :
a- f(-2)
b - f(0)
c- f ( 1/2 )
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JimmyNeutron
Verified answer
Função :
f(x) = 3x + 1
Letra a :
f(-2) = 3.(-2) + 1
f(-2) = -6 + 1
f(-2) = -5
Letra b :
f(0) = 3.0 + 1
f(0) = 0 + 1
f(0) = 1
Letra c :
23 votes
Thanks 62
Lisaah
obrigada, mas tipo, coloquei uma coisa errada, era 1/3 ...
JimmyNeutron
onde ?
Lisaah
letra c
JimmyNeutron
ok
JimmyNeutron
editei minha resposta
JimmyNeutron
resposta corrigida , novamente :)
savanna
Verified answer
Dada a função f: R ⇒R definida por f(x) = 3x + 1 , calcule :
a- f(-2)
f(-2)= 3.(-2)+1
f(-2)= -6+1
f(-2)= -5
b - f(0)
f(0)= 3.0+1
f(0)=1
c- f ( 1/3 )
f(1/3)=3.(1/3)+1
f(1/3)=3/3+1
f(1/3)= 1+1
f(1/3) =2
10 votes
Thanks 35
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Verified answer
Função :f(x) = 3x + 1
Letra a :
f(-2) = 3.(-2) + 1
f(-2) = -6 + 1
f(-2) = -5
Letra b :
f(0) = 3.0 + 1
f(0) = 0 + 1
f(0) = 1
Letra c :
Verified answer
Dada a função f: R ⇒R definida por f(x) = 3x + 1 , calcule :a- f(-2)
f(-2)= 3.(-2)+1
f(-2)= -6+1
f(-2)= -5
b - f(0)
f(0)= 3.0+1
f(0)=1
c- f ( 1/3 )
f(1/3)=3.(1/3)+1
f(1/3)=3/3+1
f(1/3)= 1+1
f(1/3) =2