Se x' e x" são zeros da função y=3x^2+4x-2, então o valor de (1/x')+(1/x") é igual a A.1/8 B.8/3 C.... Pergunta de ideia deChristopher007

Christopher007 @Christopher007

January 2020 1 98 Report

Se x' e x" são zeros da função y=3x^2+4x-2, então o valor de (1/x')+(1/x") é igual a
A.1/8
B.8/3
C.1
D.2
E.3

Lista de comentários

ProfAmaral $x'+x''=-\frac{b}{a}= -\frac{4}{3}\\ 
\\x' \cdot x''=\frac{c}{a}= \frac{-2}{3}=- \frac{2}{3}\\
\\
\\
 \frac{1}{x'} +\frac{1}{x''} =\frac{x''}{x'\cdot x''} +\frac{x'}{x'\cdot x''} =\frac{x''+x'}{x'\cdot x''} =\frac{x'+x''}{x'\cdot x''} = \frac{-4/3}{-2/3} \\
\\=( -\frac{4}{3}) \cdot(- \frac{3}{2}) = \frac{12}{6}=2$

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