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AnnaJulia2704
@AnnaJulia2704
December 2019
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A equação x² - 3 x = - 2 admite , como raiz
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rodrigoreichert
Verified answer
X² - 3x = -2
x² - 3x + 2 = 0
a = 1
b = -3
c = 2
Δ = b² - 4ac = (-3)² - 4 * 1 * 2 = 9 - 8 = 1
x' = (-b + √Δ) / 2a = (-(-3) + √1) / (2 * 1) = (3 + 1) / 2 = 4 / 2 = 2
x'' = (-b - √Δ) / 2a = (-(-3) - √1) / (2 * 1) = (3 - 1) / 2 = 2 / 2 = 1
Portanto, as raízes da equação são x = 1 e x = 2.
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AnnaJulia2704
obrigadoooo <3 , me ajudou muito
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Verified answer
X² - 3x = -2x² - 3x + 2 = 0
a = 1
b = -3
c = 2
Δ = b² - 4ac = (-3)² - 4 * 1 * 2 = 9 - 8 = 1
x' = (-b + √Δ) / 2a = (-(-3) + √1) / (2 * 1) = (3 + 1) / 2 = 4 / 2 = 2
x'' = (-b - √Δ) / 2a = (-(-3) - √1) / (2 * 1) = (3 - 1) / 2 = 2 / 2 = 1
Portanto, as raízes da equação são x = 1 e x = 2.