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AnnaJulia2704
@AnnaJulia2704
December 2019
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As raizes da equação 2 x² + 10 +12 x = 0 são
(a)= -5,-1 , (b) = -1,5 , (c) = 1,5 , (d) = 2,3
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belinha98
Letra A) -5, -1
RESOLUÇÃO:
2x^2+12x+10=0
Delta= b^2 - 4ac
Delta= 12^2 - 4. 2. 10
Delta= 144 - 80
Delta= 64
X= -b +- (raiz de delta) /2.a
X= -12 +- (raiz de 64)/ 2.2
X= -12 +- 8/ 4
X' = -12 +8/ 4
X' = -4/4 = -1
X" = -12 -8/4
X" = -20/4 = -5
(-1, -5)
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RESOLUÇÃO:
2x^2+12x+10=0
Delta= b^2 - 4ac
Delta= 12^2 - 4. 2. 10
Delta= 144 - 80
Delta= 64
X= -b +- (raiz de delta) /2.a
X= -12 +- (raiz de 64)/ 2.2
X= -12 +- 8/ 4
X' = -12 +8/ 4
X' = -4/4 = -1
X" = -12 -8/4
X" = -20/4 = -5
(-1, -5)