A equacao do 2 grau x2+x log+0,5 logt=0 a) t>0 b) t>1 c) t=0 e t=2 d) 0 e) 0 100.... Pergunta de ideia deAndrelfranca

January 2020 1 79 Report

A equacao do 2 grau x2+x log+0,5 logt=0

a) t>0
b) t>1
c) t=0 e t=2
d) 0 e) 0 100

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AlexanderHossoe X² + x log 5 - log 2 = 0

delta = log² 5 + 4 log 2 = log² 10/2 + 4 log 2 = (1 - log 2)² - 4 log 2 = 1 - 2 log 2 + log² 2 + 4 log 2 =
1 + 2 log 2 + log² 2 = (1 + log 2)²
raiz(delta) = 1 + log 2

x1 = (- log 5 + 1 + log 2) / 2 = -1 + log 2 + 1 + log 2) / 2 = 2 log 2 / 2 = log 2
x2 = (- log 5 - 1 - log 2) / 2 = -1 + log 2 - 1 - log 2) / 2 = -2/2 = -1

{-1, log 2}
Espero ter ajudado!!

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