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User2703
@User2703
January 2020
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A)12cm
b)14cm
c)16cm
d)18cm
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rosanev
Lado1 = x
Lado2 = x + 4
Amoldura = 132cm²
Afoto = 10.6 = 60cm²
Atotal = Amoldura + Afoto = 132 + 60 = 192cm²
A retângulo = Atotal = Lado1 * Lado2
192 = x(x + 4)
192 = x² + 4x
x² + 4x - 192 = 0
Δ = (4²) - 4.1.(-192) = 16 + 768 = 784
x' = (-4 + √784)/2 = -4 + 28/2 = 24/2 = 12cm
x" = (-4 - √784)/2 = - (não existe área negativa)
X= 12cm
Resposta:
A
2 votes
Thanks 1
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Lista de comentários
Lado2 = x + 4
Amoldura = 132cm²
Afoto = 10.6 = 60cm²
Atotal = Amoldura + Afoto = 132 + 60 = 192cm²
A retângulo = Atotal = Lado1 * Lado2
192 = x(x + 4)
192 = x² + 4x
x² + 4x - 192 = 0
Δ = (4²) - 4.1.(-192) = 16 + 768 = 784
x' = (-4 + √784)/2 = -4 + 28/2 = 24/2 = 12cm
x" = (-4 - √784)/2 = - (não existe área negativa)
X= 12cm
Resposta: A