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Joao3325
@Joao3325
January 2020
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Ache a fração geratriz de cada dizima a)1,715... b)1,12333... c)0,02323... d) 1,03... h)1,03030...
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Rosana2009
A) 1,712
x=1,712*(10)
10x=17,712*(100)
1000x= 1712,712
- 10x= 17,712
990x= 1695
x=1695/990
b) 1,12333
x=1,12333*(100)
100x= 112,12333
- x= 1,12333
99x= 111
x= 111/99
c) 0,02323
x=0,02323*(100)
100x= 2,02323
- x= 0,02323
99x= 2
x=2/99
d) 1,03
x= 1,03*(100)
100x= 103,03
- x= 1,03
99x= 102
x= 102/99
h) 1,03030
x=1,03030*(100)
100x= 103,03030
- x= 1,03030
99x= 102
x= 102/99
1 votes
Thanks 2
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Lista de comentários
x=1,712*(10)
10x=17,712*(100)
1000x= 1712,712
- 10x= 17,712
990x= 1695
x=1695/990
b) 1,12333
x=1,12333*(100)
100x= 112,12333
- x= 1,12333
99x= 111
x= 111/99
c) 0,02323
x=0,02323*(100)
100x= 2,02323
- x= 0,02323
99x= 2
x=2/99
d) 1,03
x= 1,03*(100)
100x= 103,03
- x= 1,03
99x= 102
x= 102/99
h) 1,03030
x=1,03030*(100)
100x= 103,03030
- x= 1,03030
99x= 102
x= 102/99