Resposta:
2 3 - λ 0
1 7 0 λ
2-λ 3
1 7-λ
det= (2-λ)*(7-λ) -3 =0
14-2λ -7λ+λ²-3=0
λ²-9λ+11=0
λ'=[9+√(81-44)]/2= (9+√37)/2
λ''=[9-√(81-44)]/2= (9-√37)/2
(9+√37)/2 e (9-√37)/2 são os autovalores de A
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Resposta:
2 3 - λ 0
1 7 0 λ
2-λ 3
1 7-λ
det= (2-λ)*(7-λ) -3 =0
14-2λ -7λ+λ²-3=0
λ²-9λ+11=0
λ'=[9+√(81-44)]/2= (9+√37)/2
λ''=[9-√(81-44)]/2= (9-√37)/2
(9+√37)/2 e (9-√37)/2 são os autovalores de A