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Mereraab
@Mereraab
April 2020
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As raizes das funções f(x) = x ao quadrado -5x + 4 definida de R em R:
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Guther
Verified answer
X² - 5x + 4 = 0
a = 1 b = - 5 c = 4
∆ = b² - 4 . a . c
∆ = (- 5)² - 4 * 1 * 4
∆ = 25 - 16
∆ = 9
x =
- b +\- √∆
x =
- (- 5) +\-
√9
2 * 1
x =
5 +\- 3
2
x' =
5 + 3
2
x' = 8
÷ 2
x' = 4
x" =
5 - 3
2
x" = 2
÷ 2
x" = 1
Resposta: {4, 1}
0 votes
Thanks 1
mozarthrocha
Verified answer
X²-5x+4=0
Δ = b²-4ac
Δ = (-5)² - 4.1.4
Δ = 25 - 15
Δ = 9
x = (-b+/-√Δ)/2a
x = (-(-5)+/-√9)/2.1
x = (5+/-3)/2
x' = (5+3)/2 --> x' = 8/2 --> x' = 4
x" = (5-3)/2 --> x" = 2/2 --> x" = 1
S:{1;4}
0 votes
Thanks 0
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Lista de comentários
Verified answer
X² - 5x + 4 = 0a = 1 b = - 5 c = 4
∆ = b² - 4 . a . c
∆ = (- 5)² - 4 * 1 * 4
∆ = 25 - 16
∆ = 9
x = - b +\- √∆
x = - (- 5) +\- √9
2 * 1
x = 5 +\- 3
2
x' = 5 + 3
2
x' = 8 ÷ 2
x' = 4
x" = 5 - 3
2
x" = 2 ÷ 2
x" = 1
Resposta: {4, 1}
Verified answer
X²-5x+4=0Δ = b²-4ac
Δ = (-5)² - 4.1.4
Δ = 25 - 15
Δ = 9
x = (-b+/-√Δ)/2a
x = (-(-5)+/-√9)/2.1
x = (5+/-3)/2
x' = (5+3)/2 --> x' = 8/2 --> x' = 4
x" = (5-3)/2 --> x" = 2/2 --> x" = 1
S:{1;4}