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creativeandco
@creativeandco
January 2021
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Bonjour, alors voilà je bloque sur cet exercice. Pouvez-vous m'aider ?
L'exercice est en pièce jointe.
J'ai réussi la question 1 mais je bloque sur la suite
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trudelmichel
Verified answer
Bonjour,
question 1
-2x²+7x+15=0
Δ=7²-4(-2)(15)
Δ=49-(-120)
Δ=49+120
Δ=169
√Δ=13
x=(-7-13)/-4 x=-20/-4 x=5
x=(-7+13)/-4 x= 6/-4 x=-2/3
question 2
(-2x²+7x+15)((2x-1)= (-4x³+14x²+30x)-(-2x²+7x+15)
-4x³+14x²+30x+2x²-7x-15=-4x³+16x²+23x-15
(-2x²+7x+15)(2x-1)=P(x)
P(x)=0
(-2x²+7x+15)(2x-1)=0
-2x²+7x+15=0 x=5 x=-2/3
2x-1=0 x=1/2
question 3
P(x)=0 x={-2/3;0;1/2
question 4
a)
P(x)-f(x)=
(-4x³+16x²+23x-15)-(23x-15)
-4x³+16x²+23x-15-23x+15
-4x³+16x²
-4x²(x-4)
P(x)-f(x)≥0
-4x²(x-4)≥0
x -∞ 0 4 +∞
-4x² - 0 - -
(x-4) - - 0 +
-4x²(x-4) + 0 + 0 -
P(x)-f(x)≥0
x ∈ ]-∞,4]
1 votes
Thanks 1
creativeandco
Est-ce que vous pourriez me numéroter les réponses svp
creativeandco
et merci beaucoup pour votre aide
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Verified answer
Bonjour,question 1
-2x²+7x+15=0
Δ=7²-4(-2)(15)
Δ=49-(-120)
Δ=49+120
Δ=169
√Δ=13
x=(-7-13)/-4 x=-20/-4 x=5
x=(-7+13)/-4 x= 6/-4 x=-2/3
question 2
(-2x²+7x+15)((2x-1)= (-4x³+14x²+30x)-(-2x²+7x+15)
-4x³+14x²+30x+2x²-7x-15=-4x³+16x²+23x-15
(-2x²+7x+15)(2x-1)=P(x)
P(x)=0
(-2x²+7x+15)(2x-1)=0
-2x²+7x+15=0 x=5 x=-2/3
2x-1=0 x=1/2
question 3
P(x)=0 x={-2/3;0;1/2
question 4
a)
P(x)-f(x)=
(-4x³+16x²+23x-15)-(23x-15)
-4x³+16x²+23x-15-23x+15
-4x³+16x²
-4x²(x-4)
P(x)-f(x)≥0
-4x²(x-4)≥0
x -∞ 0 4 +∞
-4x² - 0 - -
(x-4) - - 0 +
-4x²(x-4) + 0 + 0 -
P(x)-f(x)≥0
x ∈ ]-∞,4]